Integrand size = 23, antiderivative size = 102 \[ \int \frac {(d x)^m}{\sqrt {a+\frac {b}{\left (\frac {c}{x}\right )^{3/2}}}} \, dx=\frac {x (d x)^m \sqrt {1+\frac {b \left (\frac {c}{x}\right )^{3/2} x^3}{a c^3}} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {2 (1+m)}{3},\frac {1}{3} (5+2 m),-\frac {b \left (\frac {c}{x}\right )^{3/2} x^3}{a c^3}\right )}{(1+m) \sqrt {a+\frac {b \left (\frac {c}{x}\right )^{3/2} x^3}{c^3}}} \]
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Time = 0.06 (sec) , antiderivative size = 102, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.217, Rules used = {376, 350, 348, 372, 371} \[ \int \frac {(d x)^m}{\sqrt {a+\frac {b}{\left (\frac {c}{x}\right )^{3/2}}}} \, dx=\frac {x (d x)^m \sqrt {\frac {b x^3 \left (\frac {c}{x}\right )^{3/2}}{a c^3}+1} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {2 (m+1)}{3},\frac {1}{3} (2 m+5),-\frac {b \left (\frac {c}{x}\right )^{3/2} x^3}{a c^3}\right )}{(m+1) \sqrt {a+\frac {b x^3 \left (\frac {c}{x}\right )^{3/2}}{c^3}}} \]
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Rule 348
Rule 350
Rule 371
Rule 372
Rule 376
Rubi steps \begin{align*} \text {integral}& = \text {Subst}\left (\int \frac {(d x)^m}{\sqrt {a+\frac {b x^{3/2}}{c^{3/2}}}} \, dx,\sqrt {x},\frac {\sqrt {\frac {c}{x}} x}{\sqrt {c}}\right ) \\ & = \text {Subst}\left (\left (x^{-m} (d x)^m\right ) \int \frac {x^m}{\sqrt {a+\frac {b x^{3/2}}{c^{3/2}}}} \, dx,\sqrt {x},\frac {\sqrt {\frac {c}{x}} x}{\sqrt {c}}\right ) \\ & = \text {Subst}\left (\left (2 x^{-m} (d x)^m\right ) \text {Subst}\left (\int \frac {x^{-1+2 (1+m)}}{\sqrt {a+\frac {b x^3}{c^{3/2}}}} \, dx,x,\sqrt {x}\right ),\sqrt {x},\frac {\sqrt {\frac {c}{x}} x}{\sqrt {c}}\right ) \\ & = \text {Subst}\left (\frac {\left (2 x^{-m} (d x)^m \sqrt {1+\frac {b x^{3/2}}{a c^{3/2}}}\right ) \text {Subst}\left (\int \frac {x^{-1+2 (1+m)}}{\sqrt {1+\frac {b x^3}{a c^{3/2}}}} \, dx,x,\sqrt {x}\right )}{\sqrt {a+\frac {b x^{3/2}}{c^{3/2}}}},\sqrt {x},\frac {\sqrt {\frac {c}{x}} x}{\sqrt {c}}\right ) \\ & = \frac {x (d x)^m \sqrt {1+\frac {b \left (\frac {c}{x}\right )^{3/2} x^3}{a c^3}} \, _2F_1\left (\frac {1}{2},\frac {2 (1+m)}{3};\frac {1}{3} (5+2 m);-\frac {b \left (\frac {c}{x}\right )^{3/2} x^3}{a c^3}\right )}{(1+m) \sqrt {a+\frac {b \left (\frac {c}{x}\right )^{3/2} x^3}{c^3}}} \\ \end{align*}
\[ \int \frac {(d x)^m}{\sqrt {a+\frac {b}{\left (\frac {c}{x}\right )^{3/2}}}} \, dx=\int \frac {(d x)^m}{\sqrt {a+\frac {b}{\left (\frac {c}{x}\right )^{3/2}}}} \, dx \]
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\[\int \frac {\left (d x \right )^{m}}{\sqrt {a +\frac {b}{\left (\frac {c}{x}\right )^{\frac {3}{2}}}}}d x\]
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Exception generated. \[ \int \frac {(d x)^m}{\sqrt {a+\frac {b}{\left (\frac {c}{x}\right )^{3/2}}}} \, dx=\text {Exception raised: TypeError} \]
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\[ \int \frac {(d x)^m}{\sqrt {a+\frac {b}{\left (\frac {c}{x}\right )^{3/2}}}} \, dx=\int \frac {\left (d x\right )^{m}}{\sqrt {a + \frac {b}{\left (\frac {c}{x}\right )^{\frac {3}{2}}}}}\, dx \]
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\[ \int \frac {(d x)^m}{\sqrt {a+\frac {b}{\left (\frac {c}{x}\right )^{3/2}}}} \, dx=\int { \frac {\left (d x\right )^{m}}{\sqrt {a + \frac {b}{\left (\frac {c}{x}\right )^{\frac {3}{2}}}}} \,d x } \]
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\[ \int \frac {(d x)^m}{\sqrt {a+\frac {b}{\left (\frac {c}{x}\right )^{3/2}}}} \, dx=\int { \frac {\left (d x\right )^{m}}{\sqrt {a + \frac {b}{\left (\frac {c}{x}\right )^{\frac {3}{2}}}}} \,d x } \]
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Timed out. \[ \int \frac {(d x)^m}{\sqrt {a+\frac {b}{\left (\frac {c}{x}\right )^{3/2}}}} \, dx=\int \frac {{\left (d\,x\right )}^m}{\sqrt {a+\frac {b}{{\left (\frac {c}{x}\right )}^{3/2}}}} \,d x \]
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